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Problem-Solving and Data Analysis Difficulty: Hard
Species of treeGrowth factor
Red maple4.5
River birch3.5
Cottonwood2.0
Black walnut4.5
White birch5.0
American elm4.0
Pin oak3.0
Shagbark hickory7.5

 

One method of calculating the approximate age, in years, of a tree of a particular species is to multiply the diameter of the tree, in inches, by a constant called the growth factor for that species. The table above gives the growth factors for eight species of trees. If a white birch tree and a pin oak tree each now have a diameter of 1 foot, which of the following will be closest to the difference, in inches, of their diameters 10 years from now? (1 foot = 12 inches)

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Explanation

Choice C is correct. According to the given information, multiplying a tree species’ growth factor by the tree’s diameter is a method to approximate the age of the tree. A white birch with a diameter of 12 inches (or 1 foot) has a given growth factor of 5 and is approximately 60 years old. A pin oak with a diameter of 12 inches (or 1 foot) has a given growth factor of 3 and is approximately 36 years old. The diameters of the two trees 10 years from now can be found by dividing each tree’s age in 10 years, 70 years, and 46 years, by its respective growth factor. This yields 14 inches and 15 and one third inches. The difference between 15 and one third and 14 is 1 and one third, or approximately 1.3 inches.

Alternate approach: Since a white birch has a growth factor of 5, the age increases at a rate of 5 years per inch or, equivalently, the diameter increases at a rate of one fifth of an inch per year. Likewise, the pin oak has a growth factor of 3, so its diameter increases at a rate of one third of an inch per year. Thus, the pin oak grows two fifteenths of an inch per year more than the white birch. In 10 years it will grow two fifteenths times 10, equals four thirds of an inch more, which is approximately 1.3 inches.

Choices A, B, and D are incorrect and a result of incorrectly calculating the diameters of the two trees in 10 years.